b^2+4b+56=8

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Solution for b^2+4b+56=8 equation:


Simplifying
b2 + 4b + 56 = 8

Reorder the terms:
56 + 4b + b2 = 8

Solving
56 + 4b + b2 = 8

Solving for variable 'b'.

Reorder the terms:
56 + -8 + 4b + b2 = 8 + -8

Combine like terms: 56 + -8 = 48
48 + 4b + b2 = 8 + -8

Combine like terms: 8 + -8 = 0
48 + 4b + b2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-48' to each side of the equation.
48 + 4b + -48 + b2 = 0 + -48

Reorder the terms:
48 + -48 + 4b + b2 = 0 + -48

Combine like terms: 48 + -48 = 0
0 + 4b + b2 = 0 + -48
4b + b2 = 0 + -48

Combine like terms: 0 + -48 = -48
4b + b2 = -48

The b term is 4b.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4b + 4 + b2 = -48 + 4

Reorder the terms:
4 + 4b + b2 = -48 + 4

Combine like terms: -48 + 4 = -44
4 + 4b + b2 = -44

Factor a perfect square on the left side:
(b + 2)(b + 2) = -44

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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